16(x^2+1)=4(x+4)

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Solution for 16(x^2+1)=4(x+4) equation:


Simplifying
16(x2 + 1) = 4(x + 4)

Reorder the terms:
16(1 + x2) = 4(x + 4)
(1 * 16 + x2 * 16) = 4(x + 4)
(16 + 16x2) = 4(x + 4)

Reorder the terms:
16 + 16x2 = 4(4 + x)
16 + 16x2 = (4 * 4 + x * 4)
16 + 16x2 = (16 + 4x)

Add '-16' to each side of the equation.
16 + -16 + 16x2 = 16 + -16 + 4x

Combine like terms: 16 + -16 = 0
0 + 16x2 = 16 + -16 + 4x
16x2 = 16 + -16 + 4x

Combine like terms: 16 + -16 = 0
16x2 = 0 + 4x
16x2 = 4x

Solving
16x2 = 4x

Solving for variable 'x'.

Reorder the terms:
-4x + 16x2 = 4x + -4x

Combine like terms: 4x + -4x = 0
-4x + 16x2 = 0

Factor out the Greatest Common Factor (GCF), '4x'.
4x(-1 + 4x) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(-1 + 4x)' equal to zero and attempt to solve: Simplifying -1 + 4x = 0 Solving -1 + 4x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + 4x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + 4x = 0 + 1 4x = 0 + 1 Combine like terms: 0 + 1 = 1 4x = 1 Divide each side by '4'. x = 0.25 Simplifying x = 0.25

Solution

x = {0, 0.25}

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